//AC
#include<stdio.h>

int main() 
{ 
	int n=2;
	double m;
	double num = 0.00;
	while(1)
	{
		if(scanf("%lf",&m)==EOF)
			break;
		if(m==0.00)
			break;

		while(1)
		{
			if(num>m)
				break;
			num = num +1.0/n;
			n++;
		}
		num = 0.00;
		printf("%d card(s)\n",n-2);
		n=2;
	}
	return 0; 
} 

/*
Hangover
Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 72196		Accepted: 34240

Description

How far can you make a stack of cards overhang a table? If you have one card, you can create a maximum overhang of half a card length. (We're assuming that the cards must be perpendicular to the table.) With two cards you can make the top card overhang the bottom one by half a card length, and the bottom one overhang the table by a third of a card length, for a total maximum overhang of 1/2 + 1/3 = 5/6 card lengths. In general you can make n cards overhang by 1/2 + 1/3 + 1/4 + ... + 1/(n + 1) card lengths, where the top card overhangs the second by 1/2, the second overhangs tha third by 1/3, the third overhangs the fourth by 1/4, etc., and the bottom card overhangs the table by 1/(n + 1). This is illustrated in the figure below.


Input
The input consists of one or more test cases, followed by a line containing the number 0.00 that signals the end of the input. Each test case is a single line containing a positive floating-point number c whose value is at least 0.01 and at most 5.20; c will contain exactly three digits.

Output
For each test case, output the minimum number of cards necessary to achieve an overhang of at least c card lengths. Use the exact output format shown in the examples.

Sample Input

1.00
3.71
0.04
5.19
0.00

Sample Output

3 card(s)
61 card(s)
1 card(s)
273 card(s)

Source
Mid-Central USA 2001
*/